Extract variable

To increase my programming speed As a programmer I want to extract a variable from a selected text

Scenario: Invalid Selection
    Given a text "puts File.dirname '/tmp/file.txt'; File.dirname('/tmp/file.txt') + 'my_other_file.txt'"
    And I selected "ile.dirna"
    When I ask for refactoring options
    Then I should not be able to "Extract Variable"

Scenario: Valid Selection
    Given a text "puts File.dirname '/tmp/file.txt'; File.dirname('/tmp/file.txt') + 'my_other_file.txt'"
    And I selected "File.dirname '/tmp/file.txt'"
    When I ask for refactoring options
    Then I should able to "Extract Variable"

Scenario: Extracting a variable
    Given a text "puts File.dirname '/tmp/file.txt'; File.dirname('/tmp/file.txt') + 'my_other_file.txt'"
    And I selected "File.dirname '/tmp/file.txt'"
    When I run "Extract Variable"
    And I type "dirname"
    Then I should get "dirname = File.dirname '/tmp/file.txt'; puts dirname; File.dirname('/tmp/file.txt') + 'my_other_file.txt'"

Scenario: Extracting a variable on equal multiple occurrences
    Given a text "puts File.dirname('/tmp/file.txt'); File.dirname('/tmp/file.txt') + 'my_other_file.txt'"
    And I selected "File.dirname('/tmp/file.txt')"
    When I run "Extract Variable"
    And I type "dirname"
    And I select "All occurrences"
    Then I should get "dirname = File.dirname('/tmp/file.txt'); puts dirname; dirname + 'my_other_file.txt'"

Scenario: Extracting a variable on equivalent multiple occurrences
    Given a text "puts File.dirname '/tmp/file.txt'; File.dirname('/tmp/file.txt') + 'my_other_file.txt'"
    And I selected "File.dirname '/tmp/file.txt'"
    When I run "Extract Variable"
    And I type "dirname"
    And I select "All occurrences"
    Then I should get "dirname = File.dirname '/tmp/file.txt'; puts dirname; dirname + 'my_other_file.txt'"